\(\int \frac {1}{x^3 \log (c (a+b x^2)^p)} \, dx\) [105]

Optimal result

Integrand size = 18, antiderivative size = 18 \[ \int \frac {1}{x^3 \log \left (c \left (a+b x^2\right )^p\right )} \, dx=\text {Int}\left (\frac {1}{x^3 \log \left (c \left (a+b x^2\right )^p\right )},x\right ) \]

[Out]

Unintegrable(1/x^3/ln(c*(b*x^2+a)^p),x)

Rubi [N/A]

Not integrable

Time = 0.01 (sec) , antiderivative size = 18, normalized size of antiderivative = 1.00, number of steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {1}{x^3 \log \left (c \left (a+b x^2\right )^p\right )} \, dx=\int \frac {1}{x^3 \log \left (c \left (a+b x^2\right )^p\right )} \, dx \]

[In]

Int[1/(x^3*Log[c*(a + b*x^2)^p]),x]

[Out]

Defer[Int][1/(x^3*Log[c*(a + b*x^2)^p]), x]

Rubi steps \begin{align*} \text {integral}& = \int \frac {1}{x^3 \log \left (c \left (a+b x^2\right )^p\right )} \, dx \\ \end{align*}

Mathematica [N/A]

Not integrable

Time = 0.25 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.11 \[ \int \frac {1}{x^3 \log \left (c \left (a+b x^2\right )^p\right )} \, dx=\int \frac {1}{x^3 \log \left (c \left (a+b x^2\right )^p\right )} \, dx \]

[In]

Integrate[1/(x^3*Log[c*(a + b*x^2)^p]),x]

[Out]

Integrate[1/(x^3*Log[c*(a + b*x^2)^p]), x]

Maple [N/A]

Not integrable

Time = 0.02 (sec) , antiderivative size = 18, normalized size of antiderivative = 1.00

\[\int \frac {1}{x^{3} \ln \left (c \left (b \,x^{2}+a \right )^{p}\right )}d x\]

[In]

int(1/x^3/ln(c*(b*x^2+a)^p),x)

[Out]

int(1/x^3/ln(c*(b*x^2+a)^p),x)

Fricas [N/A]

Not integrable

Time = 0.30 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.11 \[ \int \frac {1}{x^3 \log \left (c \left (a+b x^2\right )^p\right )} \, dx=\int { \frac {1}{x^{3} \log \left ({\left (b x^{2} + a\right )}^{p} c\right )} \,d x } \]

[In]

integrate(1/x^3/log(c*(b*x^2+a)^p),x, algorithm="fricas")

[Out]

integral(1/(x^3*log((b*x^2 + a)^p*c)), x)

Sympy [N/A]

Not integrable

Time = 4.35 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.94 \[ \int \frac {1}{x^3 \log \left (c \left (a+b x^2\right )^p\right )} \, dx=\int \frac {1}{x^{3} \log {\left (c \left (a + b x^{2}\right )^{p} \right )}}\, dx \]

[In]

integrate(1/x**3/ln(c*(b*x**2+a)**p),x)

[Out]

Integral(1/(x**3*log(c*(a + b*x**2)**p)), x)

Maxima [N/A]

Not integrable

Time = 0.24 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.11 \[ \int \frac {1}{x^3 \log \left (c \left (a+b x^2\right )^p\right )} \, dx=\int { \frac {1}{x^{3} \log \left ({\left (b x^{2} + a\right )}^{p} c\right )} \,d x } \]

[In]

integrate(1/x^3/log(c*(b*x^2+a)^p),x, algorithm="maxima")

[Out]

integrate(1/(x^3*log((b*x^2 + a)^p*c)), x)

Giac [N/A]

Not integrable

Time = 0.28 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.11 \[ \int \frac {1}{x^3 \log \left (c \left (a+b x^2\right )^p\right )} \, dx=\int { \frac {1}{x^{3} \log \left ({\left (b x^{2} + a\right )}^{p} c\right )} \,d x } \]

[In]

integrate(1/x^3/log(c*(b*x^2+a)^p),x, algorithm="giac")

[Out]

integrate(1/(x^3*log((b*x^2 + a)^p*c)), x)

Mupad [N/A]

Not integrable

Time = 1.32 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.11 \[ \int \frac {1}{x^3 \log \left (c \left (a+b x^2\right )^p\right )} \, dx=\int \frac {1}{x^3\,\ln \left (c\,{\left (b\,x^2+a\right )}^p\right )} \,d x \]

[In]

int(1/(x^3*log(c*(a + b*x^2)^p)),x)

[Out]

int(1/(x^3*log(c*(a + b*x^2)^p)), x)